MHT CET202620 April 2026Evening ShiftPhysicsAlternating CurrentActual
In a L-R circuit of 4 mH inductance and 3 resistance, e.m.f. E = (1000t) V is applied. The amplitude of current is
Options
- A1.6 A
- B1 A
- C0.2 A
- D0.4 A
Correct answer
C. 0.2 A
Step-by-step solution
Given L = 4 10⁻³ H, R = 3 , and E = (1000t) V. The peak voltage is E₀ = 1 V and the angular frequency is = 1000 rad/s. The inductive reactance is X_L = L = 1000 4 10⁻³ = 4 . The impedance of the L-R circuit is Z = R^2 + X_L^2 = 3^2 + 4^2 = 5 . The amplitude of the current is I₀ = E₀ Z = 1 5 = 0.2 A. Answer: 0.2 A