MHT CET202620 April 2026Morning ShiftPhysicsAlternating CurrentActual
In a series LCR circuit, the voltage across R is 100 V, R = 1 , K , and C = 2 , F . The angular frequency is 200 rad s ⁻¹ . At resonance, the voltage across ' L ' is
Options
- A150 V
- B200 V
- C250 V
- D300 V
Correct answer
C. 250 V
Step-by-step solution
The current in the series LCR circuit is given by I = V_R R . Substituting the given values: I = 100 1000 = 0.1 A The capacitive reactance is X_C = 1 C . X_C = 1 200 2 10⁻⁶ = 10^6 400 = 2500 , The voltage across the capacitor is V_C = I X_C . V_C = 0.1 2500 = 250 V At resonance, the inductive reactance equals the capacitive reactance ( X_L = X_C ), so the voltage across the inductor equals the voltage across the capacitor. V_L = V_C = 250 V Answer: 250 V