An alternating voltage e = 150 2 100t volt is applied to a capacitor of capacity 2 F . The root mean square value of current in the circuit is

Step-by-step solution

Given alternating voltage e = 150 2 (100t) V. Comparing with the standard equation e = E₀ ( t) , we get: Peak voltage E₀ = 150 2 V Angular frequency = 100 rad/s The root mean square voltage is: E_ rms = E₀ 2 = 150 2 2 = 150 V The capacitive reactance is: X_C = 1 C = 1 100 2 10⁻⁶ = 5000 The root mean square current in the circuit is: I_ rms = E_ rms X_C = 150 5000 = 0.03 A I_ rms = 30 mA Answer: 30 mA