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MHT CET202618 April 2026Evening ShiftPhysicsAlternating CurrentActual

In the series LCR circuit shown in figure the impedance is

Options

  1. A300 ,
  2. B500 ,
  3. C700 ,
  4. D900 ,

Correct answer

B. 500 ,

Step-by-step solution

Given parameters from the circuit: Resistance, R = 300 Inductance, L = 1 H Capacitance, C = 20 F = 20 10⁻⁶ F Frequency of the AC source, f = 50 Hz The angular frequency is given by: = 2 f = 2 ( 50 ) = 100 rad/s Inductive reactance, X_L : X_L = L = 100 1 = 100 Capacitive reactance, X_C : X_C = 1 C = 1 100 20 10⁻⁶ = 1 2 10⁻³ = 500 The impedance Z of the series LCR circuit is: Z = R^2 + (X_C - X_L)^2 Substituting the values: Z = 300^2 + (500 - 100)^2 Z = 300^2 + 400^2 Z = 90000 + 160000 Z = 250000 = 500 Answer: 500 ,

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