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MHT CET202613 April 2026Evening ShiftPhysicsAlternating CurrentActual

An inductor of 0.5 mH, a capacitor of 20 F and resistance 20 , are connected in series with a 220 V ac source. If the current is in phase with the emf, the amplitude of current of the circuit is [x]^ 1/2 A. The value of x is

Options

  1. A61
  2. B121
  3. C242
  4. D442

Correct answer

C. 242

Step-by-step solution

Since the current is in phase with the emf, the circuit is in resonance. At resonance, the impedance of the circuit is equal to its resistance. Z = R = 20 , The rms current in the circuit is given by: I_ rms = V_ rms Z = 220 20 = 11 A The amplitude (peak value) of the current is: I₀ = 2 I_ rms = 11 2 = 242 A Given that the amplitude of the current is x A, we have: x = 242 x = 242 Answer: 242

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