A light bulb connected in series with a capacitor and an a.c.source is glowing with certain brightness. On reducing the value of capacitance and frequency respectively, the brightness of the bulb

Step-by-step solution

The brightness of the bulb depends on the current flowing through it, which is given by I = V Z . The impedance of the series RC circuit is Z = R^2 + X_C^2 , where X_C = 1 2 f C . When the capacitance C is reduced, the capacitive reactance X_C increases. This increases the total impedance Z of the circuit, which in turn reduces the current I . Consequently, the brightness of the bulb is reduced. Similarly, when the frequency f of the AC source is reduced, the capacitive reactance X_C increases. This again increases