In series LCR circuit R =18 and impedance is 30 . An rms voltage 210 V is applied across the circuit. The true power consumed in AC circuit is nearly

Step-by-step solution

Given a series LCR circuit with resistance R = 18 , , impedance Z = 30 , , and RMS voltage V_ rms = 210 , V , the RMS current is determined by Ohm's law: I_ rms = V_ rms Z = 210 30 = 7 , A . The true power in a resistive component is given by P = I_ rms ^2 R , yielding: P = (7)^2 18 = 49 18 = 882 , W . This result is confirmed by the alternative expression P = V_ rms ^2 R Z^2 , which evaluates to 210^2 18 30^2 = 44100 18 900 = 882 , W . The calculated power of 882 , W is closest to the option 900 , W . Final answer