Same current is flowing in two different a.c. circuits. First circuit contains only inductance and second contains only capacitance. If the frequency of a.c. is increased in both circuits, the current will

Step-by-step solution

The behavior of current with changing frequency depends on the circuit's reactive components. For a purely inductive circuit, the inductive reactance is X_L = 2 fL . Applying Ohm's law, the current becomes I_L = V/X_L = V/(2 fL) . Since f appears in the denominator, increasing the frequency causes the current to decrease. For a purely capacitive circuit, the capacitive reactance is X_C = 1/(2 fC) . The current is I_C = V/X_C = 2 fCV . Here, current increases proportionally with frequency. The analysis shows that in