In series LCR resonant circuit, R=800 , C=2 F and voltage across resistance is 200 V . The angular frequency is 250 rad / s . At resonance, the voltage across the inductance is

Step-by-step solution

Given: Series LCR circuit with R = 800 , C = 2 10⁻⁶ F, V_R = 200 V at angular frequency = 250 rad/s. At resonance, impedance becomes purely resistive, so the current is I = V_R R = 200 800 = 0.25 A. The capacitive reactance is X_C = 1 C = 1 250 2 10⁻⁶ = 1 5 10⁻⁴ = 2000 . Since X_L = X_C at resonance, the inductive reactance is also 2000 . The voltage across the inductance is therefore V_L = I X_L = 0.25 2000 = 500 V. The voltage across the inductance at resonance is 500 V .