Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202520 Apr 2025Evening ShiftPhysicsAlternating CurrentActual

The reading of the ammeter in the following circuit is

Options

  1. A3 A
  2. B6 A
  3. C12 A
  4. D9 A

Correct answer

B. 6 A

Step-by-step solution

In this series RLC circuit, the RMS source voltage is the phasor sum of the component voltages: V_ rms = V_R^2 + (V_L - V_C)^2 . Given V_L = V_C = 100 V and V_ rms = 300 V , the expression simplifies to 300 = V_R^2 + 0^2 , yielding V_R = 300 V . The RMS current is then determined from Ohm's law: I_ rms = V_R R = 300 50 = 6 A . Final answer: 6 A

Practice Alternating Current on Quantrex Academy →

More from Alternating Current

An electronic device operates at 2 MHz. The oscillating circuit has an inductance 20 10⁻⁵ H. What is the capacitive reactance of the resonant circuit? 2026When a current of 2.5 A passes through the primary coil of a transformer of 200 number turns, the magnetic flux linked with the secondary coil having 400 turns is 600 10⁻⁶ T m^2 . 2026In a given circuit, the instantaneous values of the alternating voltage and current are V = 0.5 (80 t + 3 ) volt and I = 0.5 (80 t) ampere respectively. Find the average power cons 2026A source of alternating emf = ₀ ( t) is connected to a capacitor. Then the instantaneous current in the circuit is: 2026If wattless current flows in an AC circuit, then the circuit is: 2026A solenoid having resistance R = 60 and inductance L = 0.4 H is connected to an AC source V = 100 2 200t . Find the maximum current. 2026In a circuit containing a pure resistor connected to an AC source, 2026A light bulb rated 100 W is connected to an AC source of 220 V, 50 Hz. The rms current through the bulb is 2026 Full Alternating Current list All MHT CET PYQs