In LCR series circuit, an alternating e.m.f. 'e' and current ' i ' are given by equations e =160 (100 t ) Volt and i =250 (100 t + 3 ) mA . The average power dissipated in the circuit is

Step-by-step solution

e=1.60 (100 t) volt and i =250 (100 t + 3 ) mA Comparing given equations with the standard forms, e=e₀ t and i=i₀ ( t+ ) we get, aligned & e ₀=160 ~V , I ₀=250 ~mA & Power = e ₀ 2 I ₀ 2 &= 160 250 10⁻³ 2 ( 3 ) &= 40 2 1 2 &=10 ~W aligned