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MHT CET20249 May 2024Evening ShiftPhysicsAlternating CurrentActual

An e.m.f. E=E₀ t is applied to circuit containing L and R in series. If X_L=2 R , then the power dissipated in the circuit is

Options

  1. AE_o ^2 12 R
  2. BE ₀ ^2 10 R
  3. CE ₀ ^2 8 R
  4. DE₀ ^2 6 R

Correct answer

B. E ₀ ^2 10 R

Step-by-step solution

Impedance in the circuit is given by, aligned Z^2= & R^2+X_L^2=R^2+(2 R)^2=5 R^2 P= & E₀ 2 I₀ 2 & = E₀ 2 E₀ 2 Z R Z & = E₀^2 R 2 Z^2 & = E₀^2 R 10 R^2 & = E₀^2 10 R aligned ( Z^2=5 R^2 )

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