MHT CET20243 May 2024Evening ShiftPhysicsAlternating CurrentActual
A transformer is used to set up an alternating e.m.f. of 220 V to 4.4 kV to transmit 6.6 kW of power. The primary coil has 1000 turns. The current rating of the secondary coil is (Transformer is ideal)
Options
- A0.8 A
- B1.2 A
- C1.5 A
- D1.8 A
Correct answer
C. 1.5 A
Step-by-step solution
Number of turns of in primary and secondary coil be N _ p and N _ s , For ideal transformer, aligned & N_s N_p = V_s V_p & N_s= 4.4 10^3 220 1000=2 1.0^4 aligned Power supply at primary coil is given as, aligned & P = I _ p ~V _ p =6.6 10^3 ~V & I _ p = 6.6 10^3 ~V 220 =30 ~A aligned For ideal transformer, I_s I_p = N_p N_s I _ s = 10^3 2 10^4 30=1.5 ~A