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MHT CET20243 May 2024Morning ShiftPhysicsAlternating CurrentActual

An inductance coil has a resistance of 80 . When on AC signal of frequency 480 Hz is applied to the coil, the voltage leads the current by 45^ . The inductance of the coil in henry is [ 45^ = 45^ =1 / 2 ]

Options

  1. A1 24
  2. B20
  3. C40
  4. D1 12

Correct answer

D. 1 12

Step-by-step solution

array ll & = X_L R & 45=1= 2 fL R & L= R 2 f = 80 2 480 = 1 12 array

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