In an A.C. circuit, the potential difference ' V ' and current 'I' are given respectively by V =100 (100 t ) V , I =100 (100 t + 3 ) mA The power dissipated in the circuit will be [Given 3 = 1 2 ]

Step-by-step solution

aligned & V=100 (100 t) V & I=100 (100 t+ 3 ) mA aligned Comparing these equations with the standard forms, V = V ₀ t and I = I ₀ t we get, V ₀=100 ~V , I ₀=100 10⁻³ ~A and = 3 aligned P = V _ rms I _ rms & = V ₀ 2 I ₀ 2 3 & = 100 2 100 10⁻³ 2 1 2 =2.5 ~W aligned