MHT CET202211 Aug 2022Morning ShiftPhysicsAlternating CurrentActual
A transformer having efficiency of 90 % is working on 200 ~V and 3 ~kW power supply. If the current is the secondary coil is 6 ~A , the voltage across the secondary coil and the current in the primary coil respectively are
Options
- A450 V , 12 A
- B600 V , 15 A
- C300 V , 15 V
- D450 V , 15 A
Correct answer
D. 450 V , 15 A
Step-by-step solution
Primary current, I_ P = P V = 3000 200 =15 ~A Output power =90 % of 3000 ~W =2700 ~W Therefore, voltage across the secondary coil, V_ s = 2700 6 =450 ~V