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MHT CET202210 Aug 2022Evening ShiftPhysicsAlternating CurrentActual

A capacitor 50 Fis connected to a.c. source e=220 (50 t)(e in volt , t in second). The value of peak current is

Options

  1. A0.55 2 A
  2. B2
  3. C2 0.55 A
  4. D0.55 ~A

Correct answer

A. 0.55 2 A

Step-by-step solution

Power source V=220 50 t Peak voltage V₀=220 volt So, rms voltage V_ rms = V₀ 2 = 220 2 volt Also =50 capacitive reactance X_C= 1 C = 1 50 50 10⁻⁶ =400 value of rmscurrent I_ r m s = V_ r m s X_C = 220 2 400 = 0.55 2 ampere

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