In the circuit shown, the AC source has voltage V =20 ( t ) volt with =2000 rad / s . The magnitude of amplitude current will be nearly

Step-by-step solution

Current through the circuit is given by i= V₀ R^2+ (X_C-X_L )^2 where X_L= L and X C= 1 C . Given: V ₀=20 ~V ,=6 , L =5 10⁻³ H , =2000 rad s and C =50 10⁻⁶ ~F aligned & X _ C = 1 50 10⁻⁶ 2000 10 and X _ L =2000 5 10⁻³ =10 & X _ C = X _ L aligned The current is simply: I = v ₀ R i = 20 6 ~A =3.3 ~A