MHT CET202123 Sep 2021Morning ShiftPhysicsAlternating CurrentActual
The peak value of an alternating emf ' e ' given by e = e ₀ t is 10 volt and its frequency is 50 ~Hz . At time t = 1 600 ~s , the instantaneous e.m.f is
Options
- A10 V
- B10 3 ~V
- C5 V
- D5 3 ~V
Correct answer
D. 5 3 ~V
Step-by-step solution
aligned & e = e ₀ t =10 2 ft & f =50 ~Hz , t = 1 600 ~s & e =10 100 1 600 =10 6 =5 3 ~V aligned