MHT CET202120 Sep 2021Evening ShiftPhysicsAlternating CurrentActual
When a d.c voltage of 200 ~V is applied to a coil of self-inductance ( 2 3 ) H , a current of 1A flows through it. But by replacing d.c. source with a.c. source of 200 ~V , the current in the coil is reduced to 0.5 ~A . Then the frequency of a.c. supply is
Options
- A100 ~Hz
- B60 ~Hz
- C75 ~Hz
- D50 ~Hz
Correct answer
D. 50 ~Hz
Step-by-step solution
When a d.c. voltage is applied R = V 1 = 200 1 =200 When a.c. voltage is applied aligned & Z = V 1 = 200 0.5 =400 & Z ^2= R ^2+ X _ L ^2 & (400)^2=(200)^2+ X _ L ^2 & X _ L =200 3 & 2 fL =2 f 2 3 =200 3 & f =50 ~Hz aligned