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MHT CET202120 Sep 2021Morning ShiftPhysicsAlternating CurrentActual

An inductive coil has a resistance of 100 . When an a.c. signal of frequency 1000 ~Hz is applied to the coil the voltage leads the current by 45^ . The inductance of the coil is

Options

  1. A0.25 2 H
  2. B0.05 H
  3. C0.25 H
  4. D0.5 H

Correct answer

B. 0.05 H

Step-by-step solution

= 45^ = X _ L R or X _ L = R 2 fL = R Or L= R 2 f = 100 2 1000 = 0.05 H

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