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MHT CET202020 Oct 2020Morning ShiftPhysicsAlternating CurrentActual

An e.m.f. E = E ₀ t is applied to a circuit containing 'L' and 'R' in series. If X_ L =R , then the power dissipated in the circuit is

Options

  1. AE ₀² 4 R
  2. BE ₀ 2 R
  3. CE ₀ 4 R
  4. DE ₀² 2 R

Correct answer

D. E ₀² 2 R

Step-by-step solution

E = E ₀ t P= E₀ 2 I₀ 2 = E₀ 2 E₀ 2 Z R Z = E₀² R 2 Z² Z²=R²+ L²=2 R²= E₀² R 4 R² = E₀² 4 R

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