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AIIMS 2003
Exam
AIIMS
Year
2003
Subject
Chemistry
Chapter
d and f Block Elements

AIIMS 2003 · Chemistry · d and f Block Elements

MnO_4^ 2- (1 mole) in neutral aqueous medium is disproportionated to

MnO42−(1\mathrm{MnO}_4^{2-}(1 mole) in neutral aqueous medium is disproportionated to

Options

  1. A2/3 mole of MnO4−\mathrm{MnO}_4^{-}and 1/31 / 3 mole of MnO2\mathrm{MnO}_2
  2. B1/31 / 3 mole of MnO4−\mathrm{MnO}_4^{-}and 2/3 mole2 / 3 \mathrm{~mole} of MnO2\mathrm{MnO}_2
  3. C1/31 / 3 mole of Mn2O7\mathrm{Mn}_2 \mathrm{O}_7 and 1/3 mole1 / 3 \mathrm{~mole} of MnO2\mathrm{MnO}_2
  4. D2/3 mole2 / 3 \mathrm{~mole} of Mn2O7\mathrm{Mn}_2 \mathrm{O}_7 and 1/31 / 3 mole of MnO2\mathrm{MnO}_2.

Correct answer

A. 2/3 mole of MnO4−\mathrm{MnO}_4^{-}and 1/31 / 3 mole of MnO2\mathrm{MnO}_2

Step-by-step solution

3MnO42−+2H2O→MnO2(s)+2MnO4−+4OH−3 \mathrm{MnO}_4{ }^{2-}+2 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{MnO}_{2(s)}+2 \mathrm{MnO}_4^{-}+4 \mathrm{OH}^{-} for one mole MnO42−+23H\mathrm{MnO}_{4}^{2-}+\frac{2}{3} \mathrm{H}}_{2} \mathrm{O} \rightarrow \frac{1}{3} \mathrm{MnO}_{2(s)}+\frac{2}{3} \m mathrm{MnO}}_{4}^{-}+\frac{4}{3} \mathrm{OH}^{-}
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