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NEET 2004
Exam
NEET
Year
2004
Subject
Chemistry
Chapter
d and f Block Elements

NEET 2004 · Chemistry · d and f Block Elements

Among the following series of transition metal ions, the one where...

Among the following series of transition metal ions, the one where all metal ions have 3d23 d^2 electronic configuration is: [At. no.s Ti=22, V=23,Cr=24,Mn=\mathrm{Ti}=22, \mathrm{~V}=23, \mathrm{Cr}=24, \mathrm{Mn}= 25]

Options

  1. ATi3+,V2+,Cr3+,Mn4+\mathrm{Ti}^{3+}, \mathrm{V}^{2+}, \mathrm{Cr}^{3+}, \mathrm{Mn}^{4+}
  2. BTi+,V4+,Cr6+,Mn7+\mathrm{Ti}^{+}, \mathrm{V}^{4+}, \mathrm{Cr}^{6+}, \mathrm{Mn}^{7+}
  3. CTi4+,V3+,Cr2+,Mn3+\mathrm{Ti}^{4+}, \mathrm{V}^{3+}, \mathrm{Cr}^{2+}, \mathrm{Mn}^{3+}
  4. DTi2+,V3+,Cr4+,Mn5+\mathrm{Ti}^{2+}, \mathrm{V}^{3+}, \mathrm{Cr}^{4+}, \mathrm{Mn}^{5+}

Correct answer

D. Ti2+,V3+,Cr4+,Mn5+\mathrm{Ti}^{2+}, \mathrm{V}^{3+}, \mathrm{Cr}^{4+}, \mathrm{Mn}^{5+}

Step-by-step solution

Ti22=3d24s2;Ti2+=3d2V23=3d34s2;V3+=3d2Cr24=3d44s2;Cr4+=3d2Mn25=3d54s2;Mn5+=3d2\begin{aligned}\mathrm{Ti}_{22}& =3 d² 4 s² ; \mathrm{Ti}^{2+}& =3 d² \\ \mathrm{ V}_{23}& =3 d³ 4 s² ; & \mathrm{V}^{3+} & =3 d² \\ \mathrm{Cr}_{24}& =3 d⁴ 4 s² ; \mathrm{Cr}^{4+}& =3 d² \\ \mathrm{Mn}_{25}& =3 d⁵ 4 s² ; \mathrm{Mn}^{5+}& =3 d² \end{aligned} Related Theory Mn2+\mathrm{Mn}^{2+} has the maximum number of unpaired electrons (5) and hence has the maximum magnetic moment.
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