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MHT CET202015 Oct 2020Morning ShiftPhysicsAlternating CurrentActual

A series LCR circuit has R =200 , L =663 mH and C =26 5 F . The applied alternating voltage has an amplitude of 50 ~V and a frequency of 60 ~Hz so that X _ L =250 and Xc =100 . The peak current is

Options

  1. A0.33 ~A
  2. B0 20 ~A
  3. C0.50 ~A
  4. D0 25 ~A

Correct answer

B. 0 20 ~A

Step-by-step solution

R =200 L =663 mH C =26.5 F V ₀=50 ~V , f =60 ~Hz X _ L =250 , X _ C =100 Z = R ²+ ( X ₁- X _ C )² = 40000+22500 = 62500 =250 i ₀= V ₀ Z = 50 250 = 1 5 =0.2 ~A

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