An alternating voltage is given by E = 100 sin ⁡ ω + π 6 V . The voltage will be maximum for the first time when is (T = periodic time)

Step-by-step solution

Given, alternating voltage is E = 100 sin ⁡ ω t + π 6 V The voltage will be maximum, when sin ⁡ ω t + π 6 = 1 ⇒ sin ⁡ ω t + π 6 = s i n π 2 ⇒ ω t + π 6 = π 2 ⇒ ω t = π 3 ⇒ t = π 3 ω = π × T 3 × 2 π ∵ ω = 2 π T = T 6 Thus, the voltage will be maximum for the first time when t = T 6 .