The magnetic moment of electron due to orbital motion is proportional to ( n = principal quantum number)

Step-by-step solution

Magnetic moment of an electron due to orbital motion is given by = I A . Current I = e T = e v 2 r and Area A = r^2 . = ( e v 2 r ) ( r^2) = e v r 2 Multiplying and dividing by mass m , we get = e 2m (m v r) = e 2m L From Bohr's quantization rule, angular momentum L = n h 2 . = e 2m ( n h 2 ) = n ( e h 4 m ) Therefore, n . Answer: n