The de-Broglie wavelength of an electron moving in the n^ th Bohr orbit of radius 'r' is

Step-by-step solution

According to Bohr's quantization condition, the angular momentum of an electron in the n^ th orbit is: mvr = nh 2 The de-Broglie wavelength of the electron is given by: = h p = h mv From the quantization condition, substituting mv = nh 2 r into the wavelength equation gives: = h ( nh 2 r ) = 2 r n Answer: 2 r n