If 'E' and 'L' denote the magnitude of total energy and angular momentum of revolving electron in n^ th Bohr orbit then

Step-by-step solution

The magnitude of total energy of an electron in the n^ th Bohr orbit is given by E 1 n^2 . The angular momentum of the electron in the n^ th Bohr orbit is given by L = nh 2 . This implies L n . Substituting n L in the expression for energy, we get E 1 L^2 . Thus, E L⁻² . Answer: E L⁻²