When the electron orbiting in hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it

Step-by-step solution

According to Bohr's model, the velocity of an electron in the n -th orbit is given by v 1 n . The de-Broglie wavelength of the electron is = h mv . Substituting the proportionality of velocity, we get n . The ground state corresponds to n = 1 and the third excited state corresponds to n = 4 . Since n increases from 1 to 4 , the de-Broglie wavelength of the electron will increase. Answer: will increase