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MHT CET202523 Apr 2025Evening ShiftPhysicsAtomic PhysicsActual

In hydrogen atom, transition from the state n=6 to n=1 results in ultraviolet radiation. Infrared radiation will be obtained in the transition

Options

  1. An =3 to n =1
  2. Bn =4 to n =2
  3. Cn =6 to n =2
  4. Dn =5 to n =3

Correct answer

D. n =5 to n =3

Step-by-step solution

The energy of a photon emitted during a hydrogen atom transition from n_i to n_f is given by E = 13.6 ( 1 n_f^2 - 1 n_i^2 ) eV. Spectral series identify the radiation type based on n_f : Lyman ( n_f=1 , ultraviolet), Balmer ( n_f=2 , visible), Paschen ( n_f=3 , infrared), Brackett ( n_f=4 , infrared), and Pfund ( n_f=5 , infrared). For option D ( n=5 to n=3 ), n_f=3 indicates the Paschen series, yielding infrared radiation. The energy difference is E = 13.6 ( 1 9 - 1 25 ) = 13.6 16 225 0.967 eV, corresponding to a

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