The ratio of minimum wavelengths of Lyman and Balmer series will be

Step-by-step solution

Wavelength, 1 = R ( 1 n ^2 - 1 ~m ^2 ) For shortest wavelength in Lyman series: aligned & n =1, ~m = & 1 _ L = R ( 1 1^2 - 1 ^2 )= R ...(i) aligned For shortest wavelength in Balmer series: aligned & n =2, ~m = & 1 _ B = R ( 1 2^2 - 1 ^2 )= R 4 ...(ii) aligned Dividing equation (ii) by equation (i), _ L _ B = R / 4 R = 1 4 =0.25