Ratio of longest wavelength corresponding to Lyman and Balmer series in hydrogen spectrum is

Step-by-step solution

Wavelength for Lyman series is, 1 = R [ 1 1^2 - 1 n ^2 ] For the longest wavelength, = _ and n =2 1 _ ( L ) = R [ 1 1^2 - 1 2^2 ]= 3 4 Wavelength for Balmer series is, 1 = R [ 1 2^2 - 1 n ^2 ] For the longest wavelength, n =3 aligned & 1 _ (B) = R [ 1 2^2 - 1 3^2 ]= 5 36 & _ ( L ) _ ( B ) = 4 3 5 36 = 5 27 aligned