An electron in the hydrogen atom jumps from the first excited state'to the ground state. What will be the percentage change in the speed of electron?

Step-by-step solution

Velocity of electron in the n ^ th orbit is aligned & v _ n = e ^2 2 ₀ nh & v _ n 1 n aligned Taking the ratio, v ₂ v ₁ = n ₁ n ₂ = 1 2 v ₂= v ₁ 2 Change in velocity, aligned v & = | v ₂- v ₁ | & = | v ₁ 2 - v ₁ |=0.5 v ₁ aligned Therefore, change in percentage is 50 %