A black body radiates maximum energy at wavelength ' and its emissive power is ' E ' Now due to change in temperature of that body, it radiates maximum energy at wavelength 2 3 . At that temperature emissive power is

Step-by-step solution

From Stefan-Boltzmann's law, P = dQ dt = A T ^4 Also, from Wien's displacement law, aligned & _ = b T ( b Wien's constant ) & T = b aligned aligned P & =A ( b )^4 P & 1 ( )^4 aligned Ratio of power dissipated is P ₂ P ₁ = ( ₁ ₂ )^4 Given ₁= and ₂= 2 3 . P ₂ P ₁ = ( )^4 ( 2 3 )^4 = 81 16