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MHT CET20227 Aug 2022Morning ShiftPhysicsAtomic PhysicsActual

Using Bohr's quantization, what is the rotational energy in the 2^ nd orbit for a diatomic molecule? ( I = moment of inertia of a diatomic molecule, h = Planck's constant )

Options

  1. Ah^2 2 I ^2
  2. Bh^2 I ^2
  3. Ch 2
  4. Dh 2 I ^2

Correct answer

A. h^2 2 I ^2

Step-by-step solution

According to Bohr's quantization condition: L = nh 2 = 2 ~h 2 = h [For 2^ nd orbit] The rotational KE = L ^2 2 I = h ^2 2 I ^2

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