MHT CET20227 Aug 2022Morning ShiftPhysicsAtomic PhysicsActual
An electron in stationary hydrogen atom jumps from 4^ th energy level to ground level. The velocity that the photon acquired as a result of electron transition will be ( h= Planck's constant, R= Rydberg's constant, m= mass of photon)
Options
- A11 R h 16 m
- B15 R h 16 m
- C9 R h 16 m
- D13 R h 16 m
Correct answer
B. 15 R h 16 m
Step-by-step solution
The change in energy is given by E=h c R ( 1 n₁^2 - 1 n₂^2 ) Here, energy of photon, E=R h c (1- 1 4^2 ) E= 15 16 R h c Now, energy of photon =m c^2 aligned & m c^2= 15 16 R h c & c= 15 R h 16 m aligned