Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202121 Sep 2021Evening ShiftPhysicsAtomic PhysicsActual

The wave number of the last line of the Balmer series in the hydrogen spectrum will be (Rydberg'sconstnat, . R = 10^7 ~m )

Options

  1. A16 10^4 ~m ⁻¹
  2. B8 10^5 ~m ⁻¹
  3. C36 10^7 ~m ⁻¹
  4. D25 10^5 ~m ⁻¹

Correct answer

D. 25 10^5 ~m ⁻¹

Step-by-step solution

The wave number of the last line of the Balmer series is given by 1 = R 4 = 10^7 4 =25 10^5 ~m ⁻¹

Practice Atomic Physics on Quantrex Academy →

More from Atomic Physics

What is the frequency of the electron in the first orbit of hydrogen atom of orbital radius 0.5 10⁻¹⁰ m, if its orbital velocity in that orbit is 2.2 10^6 ms⁻¹ . 2026A hydrogen atom absorbs energy and rises to n = 3 state from its ground state n = 1. If the potential energy of the atom at its ground state is -13.6eV, find the wave length emitte 2026An atom with one electron has ionization energy of 24 eV. An electron in this atom makes a transition from an excited energy level, where E = -15 eV, to the ground state. What is t 2026An atom has a single electron. Its ground state energy is -30 eV and its first excited state energy is -8 eV . The atom is bombarded with a stream of photons, each of energy 15 eV 2026The radius of first orbit in hydrogen atom is 5.3 10⁻¹¹ m. The kinetic energy E_K , potential energy E_P and total energy E_T of electron in first orbit are 2026Bohr's second postulate implies quantisation of 2026An electron transition takes place from excited state to ground state in hydrogen atom, then 2026The ratio of the shortest wavelengths of Bracket and Balmer series of hydrogen atom is 2025 Full Atomic Physics list All MHT CET PYQs