MHT CET202016 Oct 2020Morning ShiftPhysicsAtomic PhysicsActual
Using Bohr's quantization condition, what is the rotational energy in the second orbit for a diatomic molecule. (I = moment of inertia of diatomic molecule, h = Planck's constant)
Options
- An² 2 ~T ²
- Bh 2 I ²
- Ch 2 I ²
- Dn² 2 I² ²
Correct answer
A. n² 2 ~T ²
Step-by-step solution
According to Bohr's quantization condition L = nh 2 = 2 ~h 2 = h [ . For 2^ nd orbit ] Rotational KE = 1 2 L ² I = 1 2 h ² I ²