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MHT CET202015 Oct 2020Evening ShiftPhysicsAtomic PhysicsActual

Let the series limit for Balmer series be ^ ₁^ and the longest wavelength for Brackett series be ^ ₂ ^ . Then ₁ and ₂ are related as

Options

  1. A₂=0 09 ₁
  2. B₁=0 09 ₂
  3. C₁=1 11 ₂
  4. D₂=1 11 ₁

Correct answer

B. ₁=0 09 ₂

Step-by-step solution

We know, ( 1 = R ( 1 2² - 1 n ² ) ) for Balmer series ( 1 = R ( 1 4² - 1 n ² ) ) for Brackett series Now, ( 1 ₁ = R 4 ) ( 1 ₂ = R [ 1 16 - 1 25 ]= R [ 25-16 16 25 ]= 9 R 16 25 ) ( ₁ ₂ = R 4 16 25 9 R = 100 9 ) ( 9 100 ₁= ₂ ) ( ₂=0.09 ₁ )

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