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MHT CET20192 May 2019Morning ShiftPhysicsAtomic PhysicsActual

The wavelength of the first line in Balmer series in the hydrogen spectrum is ‘ λ ’. What is the wavelength of the second line in the same series?

Options

  1. A20 27 λ
  2. B3 16 λ
  3. C5 36 λ
  4. D3 4 λ

Correct answer

A. 20 27 λ

Step-by-step solution

For Balmer series. 1 λ = R 1 2 2 - 1 n 2 1 λ = R 1 4 - 1 9 1 λ = 5 R 36 …(1) For second line n = 4 1 λ 1 = R 1 4 - 1 16 = 3 R 16 …(2) By equation (1) ÷ (2) λ 1 λ = 5 38 × 16 3 ⇒ λ 1 = 20 27 λ

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