MHT CET2009PhysicsAtomic Physics
For the Bohr's first orbit of circumference 2 , the de-Broglie wavelength of revolving electron will be
Options
- A2
- B1 2 r
- C1 4 r
Correct answer
A. 2
Step-by-step solution
m v r= n h 2 , according to Bohr's theory 2 r=n ( h m v )=n for n=1, =2 r