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MHT CET202619 April 2026Morning ShiftPhysicsCapacitanceActual

A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has a thickness (4/5)d , where d is the separation of the plates. The capacitance in the presence and absence of dielectric are C and C₀ respectively. The ratio (C/C₀) is

Options

  1. AK + 4 5K
  2. B4K K + 5
  3. C5K K + 4
  4. DK + 5 4K

Correct answer

C. 5K K + 4

Step-by-step solution

The capacitance of a parallel plate capacitor without a dielectric is given by: C₀ = ₀ A d When a dielectric slab of thickness t and dielectric constant K is introduced, the capacitance becomes: C = ₀ A d - t + t K Given t = 4 5 d , substituting this value yields: C = ₀ A d - 4 5 d + 4d 5K C = ₀ A d 5 + 4d 5K C = ₀ A d(K + 4) 5K C = 5K ₀ A d(K + 4) Taking the ratio of C to C₀ gives: C C₀ = 5K K + 4 Answer: 5K K + 4

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