MHT CET202615 April 2026Evening ShiftPhysicsCapacitanceActual
Two parallel plate air capacitors are connected in parallel. Each capacitor has plate area A/2 and separation between the plates is d and 2d respectively. The equivalent capacity of the combination is ( ₀ = absolute permittivity of free space)
Options
- AA ₀ d
- B3A ₀ 4d
- C2A ₀ 3d
- DA ₀ 4d
Correct answer
B. 3A ₀ 4d
Step-by-step solution
The capacitance of a parallel plate capacitor is given by C = ₀ A' d' For the first capacitor, area A' = A 2 and separation d' = d C₁ = ₀ ( A 2 ) d = ₀ A 2d For the second capacitor, area A' = A 2 and separation d' = 2d C₂ = ₀ ( A 2 ) 2d = ₀ A 4d Since the capacitors are connected in parallel, their equivalent capacitance is the sum of their individual capacitances: C_ eq = C₁ + C₂ C_ eq = ₀ A 2d + ₀ A 4d = 3 ₀ A 4d Answer: 3A ₀ 4d