MHT CET202613 April 2026Morning ShiftPhysicsCapacitanceActual
The capacitance of a capacitor becomes 7 6 times the original value if dielectric slab of thickness t = 2d 3 is introduced between the plates, where 'd' is the distance of separation between the plates. The dielectric constant of the slab is
Options
- A9 11
- B14 11
- C8 11
- D12 11
Correct answer
B. 14 11
Step-by-step solution
The initial capacitance of the capacitor is given by: C₀ = ₀ A d When a dielectric slab of thickness t and dielectric constant K is introduced, the new capacitance becomes: C = ₀ A d - t + t K Substituting t = 2d 3 into the expression: C = ₀ A d - 2d 3 + 2d 3K C = ₀ A d 3 + 2d 3K = 3 ₀ A d (1 + 2 K ) C = 3 C₀ 1 + 2 K Given that C = 7 6 C₀ , we can equate the two expressions: 7 6 = 3 1 + 2 K 7 (1 + 2 K ) = 18 7 + 14 K = 18 14 K = 11 K = 14 11 Answer: 14 11