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MHT CET202611 April 2026Evening ShiftPhysicsCapacitanceActual

Initially, 'n' identical capacitors are joined in parallel, are charged to potential 'V'. Now they are separated and joined in series. Then

Options

  1. Apotential difference and total energy of the combination remain the same
  2. Bpotential difference remains the same and energy increases 'n' times
  3. Cpotential difference becomes 'nv' and energy remains the same
  4. Dpotential difference is 'nv' and energy increases 'n' times.

Correct answer

C. potential difference becomes 'nv' and energy remains the same

Step-by-step solution

Initial capacitance of each capacitor is C . In parallel combination, the potential difference across each capacitor is V . Charge on each capacitor, q = CV . Total initial energy, U_i = n 1 2 CV^2 . When the capacitors are separated and connected in series, the charge on each capacitor remains q = CV . The potential difference across the series combination is the sum of individual potential differences. V_f = V + V + n times = nV . Equivalent capacitance in series, C_s = C n . Total final energy, U_f = 1 2 C_s V_f

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