A parallel plate capacitor has plate area 40 cm ^2 and plates separation 2 mm. The space between the plates is filled with a dielectric medium of a thickness 1 mm and dielectric constant 5 . The capacitance of the system is

Step-by-step solution

The capacitance of a parallel plate capacitor partially filled with a dielectric is given by: C = ₀ A d - t + t K Given values are: A = 40 cm ^2 = 40 10⁻⁴ m ^2 d = 2 mm = 2 10⁻³ m t = 1 mm = 1 10⁻³ m K = 5 Substituting the values into the formula: C = ₀ 40 10⁻⁴ 2 10⁻³ - 1 10⁻³ + 1 10⁻³ 5 C = ₀ 40 10⁻⁴ 10⁻³ (1 + 1 5 ) C = ₀ 40 10⁻⁴ 10⁻³ 6 5 C = ₀ 4 10⁻³ 1.2 10⁻³ C = 4 1.2 ₀ = 40 12 ₀ = 10 3 ₀ F Answer: 10 3 ₀ F