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MHT CET202526 Apr 2025Evening ShiftPhysicsCapacitanceActual

A capacitor of unknown capacity is connected across a battery of V volt. The charge stored in it is Q coulomb. When potential across the capacitor is reduced by V₁ volt, the charge stored in it becomes Q₁ coulomb. The potential V is

Options

  1. AQ V₁ Q-Q₁
  2. BQ₁ V₁ Q+Q₁
  3. CQ₁ Q
  4. DQ Q ₁

Correct answer

A. Q V₁ Q-Q₁

Step-by-step solution

The capacitance C relates charge and voltage as Q = CV . When the potential decreases by V₁ , the new charge becomes Q₁ = C(V - V₁) . Substituting C = Q V gives Q₁ = Q V (V - V₁) , leading to Q₁ V = Q(V - V₁) . Rearranging yields V(Q - Q₁) = QV₁ , so the solution is: V = QV₁ Q - Q₁

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