MHT CET202525 Apr 2025Morning ShiftPhysicsCapacitanceActual
Five capacitors, each of capacity 'C' are connected as shown in the figure. The resultant capacity between A & B is 14 ~F . The capacity of each capacitor is
Options
- A2 F
- B3 5 ~F
- C4 F
- D2 8 ~F
Correct answer
C. 4 F
Step-by-step solution
The upper branch comprises three identical capacitors of capacitance C in parallel, producing C_ upper = C + C + C = 3C . In the lower branch, two such capacitors are in series, yielding an equivalent capacitance given by 1 C_ lower = 1 C + 1 C = 2 C , so C_ lower = C 2 . Between points A and B, these two branches are in parallel, resulting in total capacitance C_ AB = 3C + C 2 = 7C 2 . Given C_ AB = 14 , F , we solve 7C 2 = 14 , leading to 7C = 28 and thus C = 4 , F . The capacity of each capacitor is 4 , F .