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MHT CET202416 May 2024Morning ShiftPhysicsCapacitanceActual

Two identical capacitors A and B are connected in series to a battery of E.M.F., 'E'. Capacitor B contains a slab of dielectric constant K . Q _ A and Q _ B are the charges stored in A and B . When the dielectric slab is removed, the corresponding charges are Q _ A ^ and Q _ B . Then

Options

  1. AQ_A^ Q_A = K 2
  2. BQ _ B ^ Q _ B = K +1 2
  3. CQ_A^ Q_A = K+1 K
  4. DQ _ B ^ Q _ B = K +1 2 ~K

Correct answer

D. Q _ B ^ Q _ B = K +1 2 ~K

Step-by-step solution

aligned & C_A=C, C_B=K C & C_ n e t = C_A C_B C_A+C_B = C K C C+K C = ( K K+1 ) C & Q_A=Q_B= K C V K+1 aligned After the slab is removed, C_A=C ; C_B=C aligned & C _ net = C C C + C = C 2 & Q _ A ^ = Q _ B ^ = CV 2 aligned Q _ B ^ Q _ B = CV 2 KCV ~K +1 = K +1 2 ~K

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